a boy on his bike has a force of 5.6 n and is accelerating at 12/m/s/s with a speed of 17m/s what is the kinetic energy of the boy?

67.4 J

Step-by-step explanation:

F = ma

5.6 = m(12)

mass of the boy = 7/15 kg

KE = (1/2)mv^2

KE = (1/2)(7/15)(17^2)

KE = 67.4 J (3 sig. fig.)

w

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.