A box contains 22 red marbles, 55 green marbles and 55 blue marbles. ​ ​If we choose a marble, then another marble without putting the first one back in the box, what is the probability that the first marble will be green and the second will be blue?

3025/17292

Step-by-step explanation:

A box contains 22 red marbles, 55 green marbles and 55 blue marbles. ​

The total number of marbles in the box = 22 red marbles + 55 green marbles + 55 blue marbles

= 132 marbles

​If we choose a marble, then another marble without putting the first one back in the box, what is the probability that the first marble will be green and the second will be blue?

This means we are dealing with probability without replacement.

Hence:

P(Green) and P(Blue)

= P(Green) × P(Blue)

= 55/132 × 55/131

= 3025/17292

Therefore, the probability that the first marble will be green and the second will be blue is 3025/17292

i think it's b

step-by-step explanation:

because the graph is 2 above (0,0)

hey there!

if she's saving for six months, let's divide the total number we need for the trip by six, dividing it into the amount that needs to be saved for each month.

500 ÷ 6 =

she needs to save at least this amount each month, so we should use this symbol: ≥

let x be the amount she saves each month.

your final answer is x ≥

hope this !