The absolute value |x-3|<1

|x-3| < 1

make it to the possible solution

x-3 < 1 > (1)

-(x-3) < 1 > (2)

in equation (1)

x<1+3
x < 4

in equation (2)

-x + 3 < 1

-x < 1-3

-x < -2

x > 2

x ∈ (2,4)

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