Describe the behavior of the function ppp around its vertical asymptote at x=-2x=−2x, equals, minus, 2. ​

and as

Step-by-step explanation:

Given

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Required

The behavior of the function around its vertical asymptote at

Expand the numerator

Factorize

Factor out x + 1

We test the function using values close to -2 (one value will be less than -2 while the other will be greater than -2)

We are only interested in the sign of the result

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As x approaches -2 implies that:

Say x = -3

We have a negative value (-12); This will be called negative infinity

This implies that as x approaches -2, p(x) approaches negative infinity

Take note of the superscript of 2 (this implies that, we approach 2 from a value less than 2)

As x leaves -2 implies that:

Say x = -2.1

We have a negative value (-56.1); This will be called negative infinity

This implies that as x leaves -2, p(x) approaches negative infinity

So, the behavior is:

and as

answer: dead jah

step-by-step explanation:

bullet + jah= dead jah