The surface area of a regular triangular pyramid is 197.1 square meter. The slant height is 12. The area of the base is 35.1 square meters. The base length is 9 meters. What is the height of the triangular base?

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Step-by-step explanation:

(12x9/2)3=162

197.1-162=35.1

(35.1x2/2)=35.1

h = 7.8

Step-by-step explanation:

A = 1/2*b*h

35.1 = 1/2*9*h . . . . dimensions apply to the base only

35.1*2/9 = h = 7.8 . . . m is the height of the triangular base.

Check:

The base is an equilateral triangle, so the height will be (9 m)*sin(60°) = 7.8 m.

For the question asked, the surface area and slant height are irrelevant.