A hotel survey showed that nearly 30% of the guests staying at the hotel were there for personal reasons. The remainder of the guests were at the hotel on business.

Use the table of randomly generated letters to answer the questions about this scenario. The letter Prepresents personal reasons, and B
represents business reasons.

BBB PBB BPB PPB BBP
ВВР | PBB | PPB IPBB | BBP
ВВР | BPB | BBB | BBB | BBB
PPB BPB PBP BPB BBP
ВРВ | РВР | PPB IPBB | BBB

Based on this data, the estimated probability that exactly two of the three guests randomly picked were not there for personal reasons is

The estimated probability that it takes at least four guests to find one who is staying for personal reasons is

a) 32pie square meters

step-by-step explanation:

where is the graph? need more info

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.