The difference between the income and expenses are being distributed to the shareholders somewhat proportionally as shares. Accounting for the shares is not easy, because the number of shareholders is not stable since this is a startup company. On the months when income is less than expenses, the shareholders make contributions, so that the company survives the monthly losses. Under such an unpredictable situation, one of the shareholders have generated his/her own share chart, based on data from the company and his/her own monthly shares. Answer the questions below based on the data provided in Excel worksheet Q3-data.

33/100 is what i got

ur mom gay. your dad lesbian. your sister a mister. your brother a mother. your granny tranny. your grandpap a trap. your family tree lgbt.

2b2t

explanation:

2b2t

step-by-step explanation:

the line y=x is the line where the x and y coordinates of each point, are equal.

so this line is the line through the origin (0, 0), which makes an angle of 45° with the x-axis.

we draw triangle abc. to reflect this triangle with respect to the line y=x, we draw perpendiculars from the points a, b and c to to line y=x, and extend the perpendiculars so that the lint y=x is a perpendicular bisector of these line segments. 

we see that a(5, 3) is mapped to a'(3, 5)

and all the other points p(a, b) of the original triangle are mapped to p'(b,a)

the last statement is true for each point x and its reflection x', also it is true that the line y=x is the perpendicular bisector of xx' and yy'.

to prove these, check the second picture.

let the coordinates of x be (a, b), we want to find the coordinates of its reflection point with respect to the line y=x, point x'.

let m be the point on the line y=x, such that xm=mx'

let n be the point (b, b) which surely is on the line.

now, x'm=mx, nm is common and m(x'mn)=m(xmn)=90°, so by side-angle-side congruence postulate, the triangles x'mn and xmn

  are congruent, so nx=nx'

clearly the x coordinate of x' is b, so the y coordinate of x' is 

b+nx'=b+nx=a

so the coordinates of x' are (b, a)

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