In a lumberjack competition, a contestant is blindfolded and then spun around 9 times. The contestant then immediately tries to hit a single point (the target) in the middle of a horizontal log with an axe (while still blindfolded). The contestant receives 15 points if their swing is within 3cm of the target.
10 points if their swing is between 3cm and 10cm of the target.
5 points if their swing is between 10cm and 20cm of the target
zero points if their swing is further away from the target (and someone may lose a finger!).

Let Y record the position of the hit, so that Y = y > 0 corresponds to missing the target point to the right by y cm and Y = - y < 0 corresponds to missing the target to the left by y cm. Assume that Y is normally distributed with mean mu = 0 and variance 100 cm^2. Find the expected number of points that the contestant wins.

9.364 is the expected number of points.

we can approximate this to 10 points if we want a whole number

Step-by-step explanation:

We have these variables:

[0,5,10,15]

P(x= 0) = p(y>20)+p(y<-20) = 2p(y>20)

P(x=5) = p(-20<=y<=10)+p(10<=y<=20) = 2p(10<=y<=20)

P(x=10) = p(-10<=y<=-3)+p(3<=y<=10) = 2p(3<=y<=10)

P(x=15) = p(-3<=y<=3) = 2p(0<=y<=3)

Z = y/10

Therefore

P(x= 0) = 2(y>20)

= 2p(z>2) = 2(1-p<=2)

= 2(1-0.9772)

= 0.0456

P(x= 5)

= 2p(10<=y<=20)

= 2p(1<=z<=2)

= 2(0.9772-0.8413)

= 0.2718

P(x= 10)

= 2p(3<=y<=10)

= 2p(0.3<=z<=1)

= 2(0.8413-0.6179)

= 0.4468

P(x = 15)

= P(0.6179-0.3821)

= 0.2358

To get expected value of Y

0(0.0456)+5(0.2718)+10(0.4468)+15(0.2358)

= 1.359 + 4.468 + 3.537

= 9.364

E[Y] = 9.364

answer: 26

step-by-step explanation:

well, michelle wanted to measure the height of her school's flagpole she placed a mirror on the ground 48 feet from the flagpole then walk backwards until she was able to see the top of the pole in the mirror her eyes were 5 feet above the ground and she was 12 ft from the mirror using similar triangles find the height of the flagpole to the nearest tenth of a foot find the geometric mean of them pair of numbers. its easy math