If A= 5/6 ,B= 2/3,C = 9/6 then find the value of B(A+C)+C(A+B) b) a cyclist covers a distance of 15km in 2hours calculate his speed​

Step-by-step explanation:

         A = 5/6 ,      B = 2/3,         C = 9/6

B (A + C) + C (A + B)           I expanded the terms

AB + BC + AC +BC            collect the two BC terms

AB + 2BC + AC

      A = 5/6 ,      B = 2/3,         C = 9/6

AB + 2BC + AC     substiutite the values in for the variables into the eq

(5/6)(2/3) + 2(2/3)(9/6) + (5/6)(9/6)

  (10/18)  +  2 (18/18)  +  45/36

  (10/18)  +  2 (1)  +  45/36

  20/36  + 72/36 + 45/36                   2 = 72/36

    (20  + 72 + 45) / 36

         137/36                    This answer seems odd but I think it is correct

         or  3 29/36

b)  divide  15 km by 2 hours    to get the speed in   km/hr