In a poll of 2000 likely voters, 960 say that the US spends too little on fighting hunger at home. Find a 96% confidence interval for the true proportion of voters who feel this way. a. Find a point estimate for p, the population proportion who thought US spends too little on fighting hunger at home. b.Find a 96% confidence interval for p.

a. 0.48

b. The 96% confidence interval for p is (0.457, 0.503).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

In a poll of 2000 likely voters, 960 say that the US spends too little on fighting hunger at home.

This means that .

This is the answer for question a.

96% confidence level

So , z is the value of Z that has a pvalue of , so .

The lower limit of this interval is:

The upper limit of this interval is:

The 96% confidence interval for p is (0.457, 0.503).

the answer is "add 2y and y"

step-by-step explanation:

you need to collect the like terms first.

you estimate that the angle of elevation to the top of the 86th floor (the observatory) is 82 .the total height of the building is another 123 meters above the 86th floor.

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