Please help me solve this

1st pic:

x = 61

left angle = 125 degrees

right angle = 55 degrees

2nd pic:

n = 14

left angle = 78 degrees

right angle = 102 degrees

Step-by-step explanation:

1st pic:

use the following equation ⇒ 2x + 3 + x - 6 = 180

combine like terms ⇒ 3x - 3 = 180

add 6 on both sides ⇒ 3x - 3 + 3 = 180 + 3 ⇒ 3x = 183

divide both sides by 3 ⇒

x = 61

solve the angles by subtituting 61 for x

left angle = 2x + 3 ⇒ 2 x 61 + 3 ⇒ 125 degrees

right angle = x - 6 ⇒ 61 - 6 ⇒ 55 degrees

2nd pic:

use the following equation ⇒ 4n + 22 + 8n - 10 = 180

combine like terms ⇒ 12n + 12= 180

subtract 12 on both sides ⇒ 12n + 12 - 12 = 180 - 12 ⇒ 12n = 168

divide both sides by 12 ⇒

n = 14

you can find the angles by substituting 14 for n:

left angle = 4n + 22 ⇒ 4 x 14 + 22 =78 degrees

right angle: 8n - 10 ⇒ 8 x 14 - 10 = 102 degrees

s + (a + 178) = 2000

step-by-step explanation:

2000 - 178 = 1822

1822 / 2 = 911

911 + 178 = 1089

1089 + 911 = 2000

abha = 1089

shane = 911

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.