Why not when you have s+(sx)=60 divide by x to get s+s=60/x thus giving 2s=60/x
and then s = 60/2x and thus 30 /x

Well
s+sx=60
if you divided both sides by x (same as multiplying by 1/x) you would do
(1/x)(s+sx)=(1/x)60
s/x+sx/x=60/x
s/x=s=60
the division carries over to both terms

undistribute s
s(1+x)=60
divide both sides by 1+x
s=

And i oop, gurlll he not gonna have no more left .. anna ou