Acar’s stopping distance in feet is modeled by the equation d(v)= 2.15v^2/58.4f where v is the initial velocity of the car in miles per hour and f is a constant related to friction. if the initial velocity of the car is 47 mph and f = 0.34, what is the approximate stopping distance of the car?
a. 21 feet
b. 21 miles
c. 239 feet
d. 239 miles

C is the correct answer.The approximate stopping distance of the car =239 feet.

Step-by-step explanation:

Given: A car’s stopping distance in feet is modeled by the equation

where v is the initial velocity of the car in miles per hour and f is a constant related to friction.

If the initial velocity of the car v= 47 mph and f = 0.34 then

The distance of the car

≈239 feet           [ round to nearest ones]

Therefore ,the approximate stopping distance of the car =239 feet.

i think 5 miles per hour

step-by-step explanation: