4. Drew has 4 pieces of rope 1 meter long each. He cuts each rope into fifths. a. how many fifths will he have after cutting all the ropes?
b. How long will each of the fifths be in centimeters?

(Please answer the question in the next 10 minutes, thank you!)

a. 20 pieces

b. 20cm each

Step-by-step explanation:

a. 4*5=20

If he cut one of the ropes into 5 pieces, then you do the same to each of them. So that would be 5+5+5+5, which is 20.

b. 100/5=20cm

Using the question, we can assume that each rope is 1M, or 100cm. so instead of making 1meter split into 5 (which would be written as 1/5M) you instead do 100centimeters split into 5, which is 20cm each.

2^y = ln 5, or   y(ln 2) = ln 5.   solving for y,   y = (ln 5) / (ln 2).   y=5

step-by-step explanation:

the answer is: d) o, f, and kr.

atomic radius of bromine (br) is 114 pm.

atomic radius of oxygen (o) is 73 pm.

atomic radius of fluorine (f) is 72 pm.

atomic radius of krypron (kr) is 112 pm.

the atomic radius of a chemical element is a measure of the size of its atom.

the atomic radius varies with increasing atomic number, but usually increases because of increasing of number of electrons.

the atomic radius decreases across the periods because an increasing number of protons, because greater attraction between the protons and electrons.