Example 3 he two In a class of 60 students, 46 passed Biology
and 42 passed Chemistry. Every student
ariable passed at least one of the two subjects. How
many students passed in both subjects?
Solution
Let U = students in the class
cps​

28 students passed in both subjects.

Step-by-step explanation:

We solve this question treating each event as a Venn set.

I am going to say that:

Event A: Passed Biology.

Event B: Passed Chemistry.

46 passed Biology

This means that

42 passed Chemistry.

This means that

Every student passed at least one of the two subjects.

This means that

How many students passed in both subjects?

This is:

From the values we have above

28 students passed in both subjects.

6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.