Mathematics
Mathematics, 18.03.2021 02:40, golderhadashaowtatz

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Given: ae β‰… ce ; de β‰… be prove: abcd is a parallelogram. we have that ab || dc. by a similar argument used to prove that β–³aeb β‰… β–³ced, we can show that β–³ β‰… β–³ceb by. so, ∠cad β‰… ∠ by cpctc. therefore, ad || bc by the converse of the theorem. since both pair of opposite sides are parallel, quadrilateral abcd is a parallelogram.
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Mathematics, 22.06.2019 01:00, rj1262004
What is the value of x? assume that the line is tangent to the circle.
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