A big cruise ship dropped anchor off the Caribbean island of Antigua. The heavy anchor dropped into the water at a rate of 2.52.52, point, 5 meters per second. After 454545 seconds, the anchor was 404040 meters below the water's surface. From what height (above the water's surface) was the anchor released?
meters
How long did it take the anchor to reach the water's surface?
seconds

Falling at the rate of 2.5 m/s for 45 seconds, the anchor fell

                                    (2.5 m/s) x (45 s)  =  112.5 meters.

If it wound up only 40 meters underwater, then it must have fallen

                                     (112.5 m  -  40 m)  =  72.5 meters

from its storage position on the big cruise ship,

before it ever reached the water.

Since it was falling at the rate of  2.5 m/s, it took

                                    (72.5 m) / (2.5 m/s)  =  29 seconds

to get down to the water surface after it started dropping.

Step-by-step explanation:

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2