A vehicle purchased for $11,200 decreases in value at a rate of 12.1% per year. After how many years will the vehicle be worth $4,100? Round your answer to the nearest tenth of a year.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)

8p+(-9)

(-9)3p+5p and you can swith em around