The temperature at 6: 006: 00 a. m. was ‐3.5°c‐3.5°c. from 6: 006: 00 to 7: 007: 00, the temperature increased 2.5°c2.5°c. from 7: 007: 00 to 8: 008: 00, it decreased by 0.25°c0.25°c, and from 8: 008: 00 to 11: 0011: 00, the temperature dropped 3.25°c3.25°c. which expression shows the temperature in °c°c at 11: 0011: 00 a. m.?

-4.75 degree celsius

Step-by-step explanation:

We have to find  the temperature at 11:00 am

Temperature at 6:00 am =-3.5 degree celsius

Temperature increased from 6:00 to 7:00 by = 2.5 degrees celsius

Temperature at 7:00=-3.5+2.5=-1. degree celsius

The temperature decreased from 7:00 to 8:00 by =-0.25 degree celsius

Temperature at 8:00=-1.-0.25=-1.25 degree celsius

Temperature dropped from 8:00 to 11:00 by =3.35 degree celsius

Hence we take -3.5 degree celsius

Then the temperature at 11:00 am =-1.25-3.5=-4.75 degrees celsius

bull

step-by-step explanation:

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )