AT&T would like to test the hypothesis that the average revenue per retail user for Verizon Wireless customers is greater than $50. A random sample of 32 Verizon Wireless customers provided an average revenue of $54.70. It is believed that the population standard deviation for the revenue per retail user is $11.00. Using LaTeX: \alpha=0.05α = 0.05 , answer the following questions: a. Identify the null and alternative hypotheses to conduct an appropriate hypothesis test of mean. (3 points) b. Use the critical value approach to test this hypothesis. (3 points) State your decision and conclusions explicitly. (3 points) c. Use the p-value approach to test this hypothesis. (3 points) State your decision and conclusions explicitly. (3 points) d. Assume that the actual population mean for revenue per retail user is $44.30. Calculate the probability of type II error. (5 points)

An assembly consists of two mechanical components. suppose that the probabilities that the first and second components meet specifications are 0.87 and 0.84. assume that the components are independent. determine the probability mass function of the number of components in the assembly that meet specifications. x

16 more than the product of 5 and p

Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.