Is (x-4) a factor of x^3 +x^2 -16x-16x 3 +x 2 −16x−16 ?

For x – 4 to be a factor, you must have x = 4 as a zero. Using this information, I'll do the synthetic division with x = 4 as the test zero on the left:

Step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

6 and 24

step-by-step explanation:

6 x 4 = 24