Suppose that coin 1 has probability 0.7 of coming up heads, and coin 2 has probability 0.6 of coming up heads. If the coin ipped today comes up heads, then we select coin 1 to ip tomorrow, and if it comes up tails, then we select coin 2 to ip tomorrow. If the coin initially ipped is equally likely to be coin 1 or coin 2, then what is the probability that the coin ipped on the fouth day after the initial ip is coin 1? Suppose that the coin flipped on Monday comes up heads. What is the probability that the coin flipped on Friday of the same week also comes up heads? Assume that all of the flips are independent from each other.

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

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i think it might be a but you might want a second opinion

using pemdas, (order of operations) you'll see the answer is 24.

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hihi so drawing these 2 triangles is fairly simple. all that's left is finding the height of each one. luckily, we have a side length and an angle, so there is a trig function we can use to solve for the height. the easiest one to use would be tangent, since we have 2/3 things needed to find and the third needed is what we are solving for. tan(73°) * 30 ~= 98.13 and tan(73°) * 35 ~= 114.45