Solve the inequality -134< 8x-5(1-7x)

First, let's work on the left hand side of your inequality, the -134
This means, for instance, to see if it can be simplified at all.
Because of the minus sign 134 becomes - 134 The answer is -134 So, all-in-all, the left hand side of your inequality can be written as: -134 Now, let's work on the right hand side of your inequality, the 8x-5
Multiply x and 8 Multiply x and 1 The x just gets copied along. The answer is x x 8*x evaluates to 8x 8*x-5 evaluates to 8x-5 The right hand side of your inequality can be written as: 8x-5 So with these (any) simplifications, the inequality we'll set out to solve is:
-134 ‹ 8x-5
Move the -134 to the right hand side by adding 134 to both sides, like this:
To the left hand side:
-134 + 134 = 0 The answer is 0 To the right hand side:
-5 + 134 = 129 The answer is 129+8x
Now, the inequality reads:
0 ‹ 129+8x Move the 8x to the left hand side by subtracting 8x from both sides, like this:
From the left hand side:
The answer is -8x From the right hand side:
8x - 8x = 0 The answer is 129
Now, the inequality reads:
-8x ‹ 129
To isolate the x, we have to divide both sides of the inequality by the other "stuff" (variables or coefficients)
around the x on the left side of the inequality.
The last step is to divide both sides of the inequality by -8 like this:
To divide x by 1 The x just gets copied along in the numerator. The answer is x -8x ÷ -8 = x 129 ÷ -8 = Note! Here's an important point about inequalities:We are now dividing by -8, which is a number less than zero! This changes the form of your inequality. Or, in other words, your ‹ will now become a ›.The solution to your inequality is:
x ›

Solve for x by simplifying both sides of the inequality, then isolating the variable.
x > -3.

Period is the time it takes for one “cycle” to complete. in the parent sine function, period is 2*pi since sin(0) = 0, sin(pi/2) = 1, sin(pi) = 0, sin(3pi/2) = -1, and sin(2pi) = 0. at that point, the sequence repeats itself. i’m not sure if your graph is similar to the sine function since you didn’t provide a picture, but you can find the period by looking at a graph.