A ranch hand herded his cattle to some grazing land. Then he began riding back to the ranch, which is due west, at 7 miles per hour. Simultaneously, the cows began moving away from
him, too, headed due east at 3 miles per hour. How long did it take for the herd and the
ranch hand to be 2 miles apart? (Please help me !!)

1/5 hr or 12 min

Step-by-step explanation:

We are going to use the formula D = RT

Let t = the time for  them to be 2 mi. apart

Then 7t = the distance the ranch hand traveled

and 3t = the distance the cows traveled

Since they traveled in opposite directions, the sum of their distances will give us how far they are apart.

So, 7t + 3t = 2

10t = 2

t = 2/10 = 1/5 hr. =  12 min.

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value