CAN SOMEONE PLEASE ME... If k=
, rewrite
in terms of k.​

Using the inverse formula of the first equation we have: k^2=3

Since 48 is 16 times 3 then 48 = 16k ^ 2

So it becomes log2(16k^2)= 2log2(16k)

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)