Each car on a computer train holds 20 people. On a particular morning, 5 cars were 90% full and 3 cars were 65% full. If the people were rearranged to fill as many cars as possible, how many cars would be filled?

7 cars

Step-by-step explanation:

The computation of the number of cars to be filled is shown below:

A car that is 90% full and the total people is 20 so 90% would be

= (.90)(20)

= 18

A car that is 65% full and the total people is 20 so 65% would be

= (.65)(20)

= 13

Now

Total number of people = (5)(18) + (3)(13).

= 129

Now the number of cars to be filled is

= 129 ÷ 20

= 6.45

= 7 cars

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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