Mathematics, 13.03.2021 07:20, 109077
En el menú de restaurante hay 6 platillos, 5 bebidas y 9 postres, si el comensal eligiera 1 platillo, 2 bebidas y 2 postres ¿de cuántas maneras sería posible?
Answers: 1
Mathematics, 21.06.2019 12:30, wcraig1998
Use the function nest to evaluate p(x) = 1 + x + · · · + x50 at x = 1.00001. (use the matlab ones command to save typing.) find the error of the computation by comparing with the equivalent expression q(x) = (x51 − 1)/(x − 1).
Answers: 3
Mathematics, 21.06.2019 16:30, angeline310
Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane
Answers: 2
En el menú de restaurante hay 6 platillos, 5 bebidas y 9 postres, si el comensal eligiera 1 platillo...
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