HELP NEED THIS FOR A TEST Diego's family car holds 14 gallons of fuel. Each day the car uses 0.6 gallons of fuel. A warning light comes on when remaining fuel is 1.5 gallons or less.

a.

capacity of car = 14 gallons

consumption of fuel in one day = 0.6 gallons

consumption of fuel in 14 days = 14 x 0.6 = 8.4 gallons

fuel remaining in car = 14 - 8.4 = 5.6 gallons

so they can drive the car without warning.

b.

consumption of fuel in one day = 0.6 gallons

consumption of fuel in 25 days = 25 x 0.6 = 15 gallons

fuel remaining in car = 14 - 15 = -1 gallons

so they can't drive the car without warning.

c.

the expression 14 - 0.6t represents remaining fuel in the vehicle, where t represents number of days.

d.

14 - 0.6t = 1.5

or - 0.6t = 1.5 - 14 = - 12.5

or t = -12.5 / - 0.6

or t = 20.8333 days

so he can drive 20 days without warning.                                                                                         E.

14 - 0.6t < 1.5

or t < 20.8333

here t represents number of days car can drive without warning light.

Step-by-step explanation:

The inequality is  

The maximum number of days that Diego's father can drive the car without the warning light coming on is 20 days

14 gallons-1.5 gallons=12.5 gallons  

we know that

If the remaining fuel is greater than  1.5 gallons Diego's father can drive the car without the warning light coming on  

so

Let

x > the number of days

 > inequality that represent the situation

Solve for x

The maximum number of days that Diego's father can drive the car without the warning light coming on is 20 days

sorry man i accidentally pressed yes my bad

step-by-step explanation:

answer: the is put the 450

step-by-step explanation: