Estimate the perimeter of the figure to the nearest whole number.

 perimeter 28 units

==========================================================

Explanation:

Refer to the diagram below. In figure 1, I'm showing how the purple side A moves outward to the left, and the green side B moves up. This effectively expands the corner out, but we keep the same perimeter (since sides A and B didn't change in length). Apply these sort of steps to each of the four corners and you'll get what you see in figure 2. The purple box has the same perimeter as the orange original figure.

Why go through these steps? Because it's much easier to find the perimeter of a rectangle than the perimeter of some complicated shape like this. The purple rectangle in figure 2 has horizontal length of 8 units, and the vertical width is 6 units.

The perimeter of the purple rectangle is

P = 2*(length+width)

P = 2*(8+6)

P = 2*14

P = 28

Or you could say: 8+6+8+6 = 14+14 = 28

The purple rectangle in figure 2 has perimeter of 28 units, so the orange figure also has the same perimeter.

---------------

Another approach to find the perimeter is to ignore figures 1 and 2, and simply count the number of edges along the outside. You should count 28 in total. I recommend you mark each side counted with a value so you don't lose track.

step-by-step explanation:

the areas of two similar triangles are 18 cm2 and 8 cm2. one of the sides of the first triangle is 4.5 cm. what is the length of the corresponding side of the other triangle?

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.