The height in ft of a rocket after x seconds is given by y=128-16x^2y. What is the maximum height reached by the rocket, and how long does it take the rocket to reach max height.

Max height = 128feet

Time = 0secs

Step-by-step explanation:

Given the height in ft of a rocket after x seconds is given by y=128-16x^2, at maximum height, the velocity of the object is zero that is;

dy/dx = 0

0 - 32x = 0

x = 0/-32

x = 0

Hence the time taken for the object to reach its maximum height is 0 secs

To get the maximum height reached, you will substitute x = 0 into th expression given as shown;

y = 128 - 16x^2

y = 128 - 16(0)^2

y = 128 - 0

y = 128feet

Hence the maximum height reached by the rocket is 128feet

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step-by-step explanation:

4th option is correct xy=-10

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