Investigate the following harvesting model both qualitatively and analytically. If a constant number h of fish are harvested from a fishery per unit time, then a model for the population P(t) of the fishery at time t is given by dP dt = P(a − bP) − h, P(0) = P0, where a, b, h, and P0 are positive constants. Suppose a = 9, b = 1, and h = 81 4 . Determine whether the population becomes extinct in finite time. The population becomes extinct in finite time for all values of P0. The population becomes extinct in finite time if P0 < 9 2 . The population does not become extinct in finite time. The population becomes extinct in finite time if P0 > 9 2 . The population becomes extinct in finite time if P0 = 9 2 . If so, find that time. (If not, enter NONE.)

false

step-by-step explanation:

i looked it up

x+y = 29, 5x + 2y = 100

step-by-step explanation:

i'm guessing it was a multiple first option was the correct answer

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29