Kiran, Mai, and Tyler went to their school carnival. They all won chips that they could exchange for prizes. Kiran won 2/3 as many chips as Jada, Mai won 4 times as many chips as Kiran. Tyler won half as many chips as Mai. If Jada won 42 chips, how many chips did Tyler, Kiran, and Mai each win?

k = 28

m = 112

t = 56

Step-by-step explanation:

From the question, the following equations can be derived

Kiran's chips (k) = 2/3 x J

Mai (M) = 4 x k

Tyler = 1/2 x M

If Jada won 42 chips, Kiran's chips (k) = 2/3 x 42 = 28

Mai = 4 x 28 = 112

Tyler = 1/2 x 112 = 56

its 69.420

step-by-step explanation:

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2