2 cos(x + 40°) = for 0 < x < 360° Solve equation for x

Please include full solution

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

yes

step-by-step explanation:

i hope this is what you were looking for.

see attached graph