Given the equation Square root of 2x plus 1 = 3, solve for x and identify if it is an extraneous solution

To answer the question above, raise both sides of the equation to the power of two.
(sqrt (2x + 1))² = 3²
This will simplify into,
2x + 1 = 9
Solving for the value of x gives an answer of x = 4. This value is not an extraneous root as it satisfy the original equation even if it is inside the radical sign. (I hope this is right)

Use socratic. Hold up lemme find the answer