z2=1+i √3
(z1*z2)^8=?
Mathematics, 11.03.2021 23:20, Yeajay6313
Can you help me with these exercises
1. z1=cos*pi/8+i*sin*pi/8;
z2=1+i √3
(z1*z2)^8=?
2.Solve in C ecuation z^4+81=0
3.Solve ecuation x^3-4x^2+x+6=0
Answers: 1
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Do you know the correct answer?
Can you help me with these exercises
1. z1=cos*pi/8+i*sin*pi/8;
z2=1+i √3
(z1*z2)^8=?
z2=1+i √3
(z1*z2)^8=?
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