Mathematics, 11.03.2021 23:20, isudgyia

1) 2cos^2 θ=1, [0,2pi)
2) (cscθ -2)(csc θ+ √2) = 0, [0,2pi)
3) cot^3 θ = cot θ, [0,2pi)

Answers: 3

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1) 2cos^2 θ=1, [0,2pi)
2) (cscθ -2)(csc θ+ √2) = 0, [0,2pi)
3) cot^3 θ = cot θ, [0,2pi)...