Mathematics, 11.03.2021 19:50, dorothylankford3823
select all the equations that have no solution x +6 = 5+ x. -2 ( x -3 ) = - 2x +6. 4 (x + 1 ) = 3 ( x+2). 5- 3x = - 3x +4 and is it possible if you can plss show the work ?
Answers: 3
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For [tex]f(x) = 4x + 1[/tex] and (x) = [tex]g(x)= x^{2} -5,[/tex] find [tex](\frac{g}{f}) (x)[/tex]a. [tex]\frac{x^{2} - 5 }{4x +1 },x[/tex] ≠ [tex]-\frac{1}{4}[/tex]b. x[tex]\frac{4 x +1 }{x^{2} - 5}, x[/tex] ≠ ± [tex]\sqrt[]{5}[/tex]c. [tex]\frac{4x +1}{x^{2} -5}[/tex]d.[tex]\frac{x^{2} -5 }{4x + 1}[/tex]
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select all the equations that have no solution x +6 = 5+ x. -2 ( x -3 ) = - 2x +6. 4 (x + 1 ) = 3 (...
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