Three red rods are 2 cm longer than two blue rods. Three blue rods are 2 cm longer than four red rods. How long is each rod? The answer is blue equals 14 cm and red
equals 10 cm. Which system of equations must be solved?
3r - 2 = 2b
3b - 2 = 4r
3r = 2b - 2
3b = 4r - 2
3r + 2 = 2b
3b + 2 = 4r
3r + 2 > 2b
3b > 2 + 4r

i dont know

step-by-step explanation:

umm. i dont know

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!

at least two

step-by-step explanation:

step-by-step explanation:

f(gx)=f(1/x+2)

=(1/x+2)+2

=(1+2x)/2+2

=(1+2x+4)/2

= (2x+5)/2