WILL GIVE BRAINLIEST! NEED INSTANT HELP! NEED ANSWER FAST! The distance s, in feet, that an object will fall in t seconds is given by the formula
s = 16t2 + vt,
where v is the initial velocity of the object in feet per second.

Find the initial velocity of an object that falls 96 ft in 2 s.
ft/s

vi = 16ft/s

Step-by-step explanation:

96 = 16(2)² + 2v

2v = 96 - 64

2v = 32

v = 16

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

the answer is c

step-by-step explanation: