Explain how to find the value of y in the equation 6(y+4)=12

y=-2 (Please can i have brainliest)

Step-by-step explanation:

There are different ways to do this but my way, you would distribute 6 to both y and 4, ending up with 6y+24=12. You then subtract 24 from both sides giving you, 6y=-12. Then divide both sides by 6, giving you y=-2

y=-2

Step-by-step explanation:

First, you would distribute the 6 to both the y and the 4 which would give you 6y+24=12

Then you would subtract 24 from 12 to get -12 ( it would look like 6y= -12 after)

Finally, you would take -12/6 to get -2 so y = -2

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

if i put something wrong your not gonna like it so rather not say nothing.