(order doesn't matter)

Because there are 4 ways to pick red then 4 (C)

Possible outcomes that contain at least one red tile = 7

Step-by-step explanation:

Number of blue tile = 1

Number of green tile = 1

Number of red tile = 1

Number of yellow tile = 1

Total number of tiles = 4

Possible number of outcomes in choosing one tile = 4

Possible number of outcomes in selecting the second tile = 4

⇒ Possible number of outcomes in selecting both the tiles = 4 × 4 = 16

We need to find the find the possible outcomes that contain at least one red ⇒ One tile must be at least of red color.

Now, Possible outcomes of selecting first tile if not red = 3

Possible outcomes of selecting second tile if not red = 3

⇒ Possible outcomes of selecting both the tiles if not red = 3 × 3 = 9

Hence, Possible outcomes that contain at least one red tile = 16 - 9 = 7

Here's an another way to answer this question:

How many ways can we pick a tile and then a red tile

4* 1  = 4   (this approach gives us the red-red combo

and how many was can we pick a red and then a non red

1*3 = 3

now we combine these to get the 7 possible choices with red

usually it is easier to solve these type of problems using the first approach that I illustrated.

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: