Plz help me guys I really need it... :/

for this equation use photomath this app helps you solve any problem hope this helps!

v: l•w•h÷2.

v: 20•6•8 ÷2

v: 960÷2

v: 480

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐