A rectangle lengths 12m and 17m and is dilated using the dilation (x, y) -> ( 0.4 x, 0.4y). What is the perimeter of the dilated rectangle?

Perimeter of the dilated rectangle = 23.2 m

Step-by-step explanation:

If a point is dilated by a scale factor = k

Coordinates of the image point after dilation will follow the rule,

(x, y) → (kx, ky)

From the given rule,

(x, y) → (0.4x, 0.4y)

Which reveals that the figure has been dilated by a scale factor = 0.4

Length of the rectangle = 12 m

Width of the rectangle = 17 m

If the given rectangle is dilated by a scale factor of 0.4,

Length of the image rectangle = 12 × 0.4 = 4.8 m

Width of the image rectangle = 17 × 0.4 = 6.8 m

Perimeter of a rectangle = 2(length + width)

Therefore, perimeter of the image rectangle = 2(4.8 + 6.8)

                                                                           = 23.2 m

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

sorry, i can't understand your question. will later if you describe more clearly!

: )