I need help on the 3rd question in Part A nd Part B (06.01)The scatter plot shows the relationship between the test scores of a group of students and the number of hours they spend on social media in a week:

A scatter plot is shown. The x-axis is labeled Hours spent on social media, and the y-axis is labeled test score. Data points are located at 0.5 and 100, 2 and 100, 1 and 95, 3 and 85, 3 and 78, 5 and 75, 5 and 72, 6 and 70, 6 and 98, 7 and 60. A circle labeled A includes all of the points except for the one at 6 and 98. Point 6 and 98 is labled B.

Part A: What is the group of points labeled A called? What is the point labeled B called? Give a possible reason for the presence of point B. (3 points)
Part B: Describe the association between a student’s test scores and the number of hours spent on social media. (2 points)

For A it is going to be for the group called P is going to be a cluster and the point called T is an outlier. For B, it is going to be if the students exercise more their scores will go up.

Step-by-step explanation:

For A, the reason why P is a cluster is because all of those points are  bunched together in a positive linear association, and for T the reason why it is called an outlier is because it is not in the line or cluster with all of the other points in P. For B, you can see that in the cluster, whenever the hours of exercise go up, the test scores go up also, this is why it is a positive linear association.

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places