2x+3y=5x-y2x+3y=5x−y2, x, plus, 3, y, equals, 5, x, minus, y Complete the missing value in the solution to the equation. ((left parenthesis ,0),0)comma, 0, right parenthesis

The first one, i believe, would be correct. all the others have one thing in common, and that's that they have repeating numbers. in the second one, x and y have repeating 6's and 3's, and in the third, x and y have repeating 6's as well. in the last one, there are repeating 3's. the first one has no repeating numbers.

Ithink it would be 160 people