I need help very fast please !

Jump discontinuity at x = -2 & infinite discontinuity at x = 0.

Step-by-step explanation:

Hi again,

In this example, we see that there is a jump discontinuity at x = -2 because the line hypothetically "jumps" from y = 2 to y = 0. (just a way to remember these terms)

In addition, there is an infinite discontinuity at x = 0 because the green function will become infinitely close to x = 0 but never crosses nor touches it.

Hope this explanation was helpful. Cheers.

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180