Write a polynomial functionſ of least degree that has rational coefficients, a leading coefficient of 1, and the zeros 1,3, and 2-i.

f(x) =

Step-by-step explanation:

First of all, if 2 - i is a zero, then so is 2 + i

All you need to do now is multiply (x - 1)(x - 3)(x - 2 + i)(x - 2 - i)

I will do part of that multiplication

(x - 2 + i)(x - 2 - i) = - 2x - xi - 2x + 4 + 2i + xi - 2i -

                           = - 4x + 5

So, now (x - 1)(x - 3)( - 4x + 5) =  

I will let you finish that multiplication.  I did some and you can do some.  OK?

step-by-step explanation:

∆abc has the points a(1, 7), b(-2, 2), and c(4, 2) as its vertices. formed with the point d(1, 2) as its third vertex, then ∆abd is triangle.