Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total of people 13 took the trip. She was able to purchase coach tickets for ​$390 and first class tickets for ​$1000. She used her total budget for airfare for the​ trip, which was ​$8120. How many first class tickets did she​ buy? How many coach tickets did she​ buy?

x = 6

Step-by-step explanation:

Coach ticket = $180

first class ticket = $1020

people = 8

Let x be number of coach tickets

Then number of first class tickets = (8 - x)

x * 180 + (8 - x) * 1020 = 3120

180 X + 8 * 1020 - 1020 x = 3120

180 x + 8160 - 1020 x = 3120

180 x - 1020 x = 3120 -8160

- 840 x = - 5040

840 x = 5040

x = 6

So 6 coach class tickets and 2 first class tickets

She bought 8 coach tickets

And 5 first class tickets

Step-by-step explanation:

390 x 8 = 3,120

1000 x 5 = 5,000

3,120 + 5,000 = 8,120

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47