WILL GIVE BRAINLIEST PLEASE HELP: In rectangle ABCD the diagonals intersect each other at point O and m ABD = 30 degrees. Find BC if AC = 16 in.

AngleCOD=angle AOB=62°

As AO=OC=BO=OD

In triangle OCD, OC=OD

Hence angle ODC=(180–62) /2( sum of angle of triangle is 180°)

=118/2 =59°

Step-by-step explanation:

8

Step-by-step explanation:

We know that ABD is 30 degrees. To find BC, we need to use sin.

Equation:

BC = 16*sin(30 degrees) I recommend using a calculator to find the sine if you don't know what it means and how to use it. Sine is basically the side length opposite of the angle over the hypotenuse of the right triangle.

BC = 16*0.5

BC = 8

Sorry, I couldn't find an image.

Hope this helps!

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

the answer is mp

step-by-step explanation: