Write the equation of the line that passes through the points (4,8) and (1,-8). Put your answer in fully reduced point-slope form, unless it is a vertical or horizontal line. Pleaseee help me:/

y = (16/3)*x - 13.33

Step-by-step explanation:

A linear relationship can be written as:

y = a*x + b

where a is the slope and b is the y-axis intercept.

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1).

Then for our particular case, we know that the line passes through the points (4, 8) and (1, -8)

Then the slope for this line will be:

a = (8 - (-8))/(4 - 1) = 16/3

Then our line is something like:

y = (16/3)*x + b

We need to find the value of the y-intercept b.

We know that this line passes through the points (4, 8) and (1, -8)

Then we can just replace the values of one of these points in our linear equation, for example, if we se the first one we get:

x = 4 and y = 8

replacing that in our equation we get:

8 = (16/3)*4 + b

8 - (16/3)*4 = b

-13.33 = b

Then the equation for our line is:

y = (16/3)*x - 13.33

triangle abc is reflected on the line x=-6.5 then reflected again on the x axis

step-by-step explanation: